5/x^2=7/(1-x)^2

Solution for 5/x^2=7/(1-x)^2 equation:

5/x^2=7/(1-x)^2

We move all terms to the left:

5/x^2-(7/(1-x)^2)=0


Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R



Domain of the equation: (1-x)^2)!=0

We move all terms containing x to the left, all other terms to the right

-x)^2!=-1

x!=-1/1

x!=-1

x∈R


We add all the numbers together, and all the variables

5/x^2-(7/(-1x+1)^2)=0

We calculate fractions


(-5x)/(x^2*(-1x+1)^2))+(-(7*x^2)/(x^2*(-1x+1)^2))=0


We calculate terms in parentheses: -(7*x^2)/(x^2*(-1x+1)^2)), so:

7*x^2)/(x^2*(-1x+1)^2)

We multiply all the terms by the denominator


7*x^2)

Wy multiply elements

7x^2

Back to the equation:

-(7x^2)


determiningTheFunctionDomain
-7x^2+(-5x)/(x^2*(-1x+1)^2))+(=0

We multiply all the terms by the denominator


-7x^2*(x^2*(-1x+1)^2))+(+(-5x)=0

We get rid of parentheses

-7x^2*(x^2*(-1x+1)^2))+(-5x=0